Sine Rule

The sine rule is used to find missing sides or angles in non-right-angled triangles when you know an opposite side-angle pair. Match each side with the angle opposite it, then use \(\dfrac{a}{\sin A} = \dfrac{b}{\sin B}\) to find a missing side. When two sides and one angle are given, flip the sine rule to \(\dfrac{\sin A}{a} = \dfrac{\sin B}{b}\) to find a missing angle.

Common mistake: Always pair a side with its opposite angle. If side \(c\) is opposite angle \(C\), use \(\dfrac{c}{\sin C}\), not \(\dfrac{c}{\sin B}\).

Worked example:
In the triangle, \(A=35^\circ\), \(B=70^\circ\), and \(a=9\text{ cm}\). Find \(b\), to 1 decimal place.
Triangle with angle A 35 degrees, angle B 70 degrees, side a 9 cm opposite A, and side b marked x opposite B.
  1. Use the sine rule.
    \[\dfrac{b}{\sin70^\circ}=\dfrac{9}{\sin35^\circ}\]
    \[b=\dfrac{9\sin70^\circ}{\sin35^\circ}=14.7\]
Answer:
\(b = 14.7\text{ cm}\).
Worked example:
In the triangle, \(A=48^\circ\), \(a=10\text{ cm}\), and \(b=8\text{ cm}\). Find \(B\), to 1 decimal place.
Triangle with angle A 48 degrees, side a 10 cm opposite A, side b 8 cm opposite angle B, and angle B marked x.
  1. Use the sine rule to find \(\sin B\).
    \[\dfrac{\sin B}{8}=\dfrac{\sin48^\circ}{10}\]
    \[\sin B=\dfrac{8\sin48^\circ}{10}\]
    \[B=\sin^{-1}\left(\dfrac{8\sin48^\circ}{10}\right)=36.5^\circ\]
Answer:
\(B = 36.5^\circ\).